Problem 463 Island Perimeter
Table of Contents
Problem Statement
Link - Problem 463
Question
You are given row x col grid
representing a map where grid[i][j] = 1
represents land and grid[i][j] = 0
represents water.
Grid cells are connected horizontally/vertically (not diagonally). The grid
is completely surrounded by water, and there is exactly one island (i.e., one or more connected land cells).
The island doesn’t have “lakes”, meaning the water inside isn’t connected to the water around the island. One cell is a square with side length 1. The grid is rectangular, width and height don’t exceed 100. Determine the perimeter of the island.
Example 1
Input: grid = [[0,1,0,0],[1,1,1,0],[0,1,0,0],[1,1,0,0]]
Output: 16
Example 2
Input: grid = [[1]]
Output: 4
Example 3
Input: grid = [[1,0]]
Output: 4
Constraints
- row ==
grid.length
- col ==
grid[i].length
1
<= row, col <=100
grid[i][j]
is0
or1
.- There is exactly one island in grid.
Solution
class Solution {
public:
int islandPerimeter(vector<vector<int>>& grid) {
int row = grid.size(), col = grid[0].size();
int peri = 0;
for(int i=0;i<row;i++)
{
for(int j=0;j<col;j++)
{
if(grid[i][j]&1)
{
peri+=4;
if(i>0 && (grid[i-1][j] & 1))
peri-=2;
if(j>0 && (grid[i][j-1] & 1))
peri-=2;
}
}
}
return peri;
}
};
Complexity
Time : O(N*M)
Space : O(1)
Explanation
- We iterate over the grid.
- If the cell is land then add 4 to the perimeter.
- Then we check the left and top of the cell.
- If they are land then we subtract 2 from the perimeter each.
- This is because when two lands are adjacent then they share a side and hence the perimeter is reduced by 2.
- Finally return the perimeter.
This problem demonstrates the traversal of a matrix and checking the adjacent cells.